10113311011 has 4 divisors (see below), whose sum is σ = 10251849592. Its totient is φ = 9974772432.

The previous prime is 10113311003. The next prime is 10113311023. The reversal of 10113311011 is 11011331101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11011331101 = 337 ⋅32674573.

It is a cyclic number.

It is not a de Polignac number, because 10113311011 - 2³ = 10113311003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10113310982 and 10113311000.

It is not an unprimeable number, because it can be changed into a prime (10113311041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69269181 + ... + 69269326.

It is an arithmetic number, because the mean of its divisors is an integer number (2562962398).

Almost surely, 2^10113311011 is an apocalyptic number.

10113311011 is a deficient number, since it is larger than the sum of its proper divisors (138538581).

10113311011 is an equidigital number, since it uses as much as digits as its factorization.

10113311011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138538580.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 10113311011 its reverse (11011331101), we get a palindrome (21124642112).

The spelling of 10113311011 in words is "ten billion, one hundred thirteen million, three hundred eleven thousand, eleven".