101133113131 has 8 divisors (see below), whose sum is σ = 102461284800. Its totient is φ = 99806141760.

The previous prime is 101133113129. The next prime is 101133113143. The reversal of 101133113131 is 131311331101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101133113131 - 2¹ = 101133113129 is a prime.

It is a super-2 number, since 2×101133113131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101133113099 and 101133113108.

It is not an unprimeable number, because it can be changed into a prime (101133113111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129826 + ... + 468103.

It is an arithmetic number, because the mean of its divisors is an integer number (12807660600).

Almost surely, 2^101133113131 is an apocalyptic number.

101133113131 is a deficient number, since it is larger than the sum of its proper divisors (1328171669).

101133113131 is an equidigital number, since it uses as much as digits as its factorization.

101133113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600149.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 101133113131 its reverse (131311331101), we get a palindrome (232444444232).

The spelling of 101133113131 in words is "one hundred one billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred thirty-one".