1011341254443 has 8 divisors (see below), whose sum is σ = 1452182314128. Its totient is φ = 622363848864.

The previous prime is 1011341254393. The next prime is 1011341254477. The reversal of 1011341254443 is 3444521431101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1011341254443 - 2⁶ = 1011341254379 is a prime.

It is a super-2 number, since 2×1011341254443² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1011341258443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12965913480 + ... + 12965913557.

It is an arithmetic number, because the mean of its divisors is an integer number (181522789266).

Almost surely, 2^{1011341254443} is an apocalyptic number.

1011341254443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1011341254443 is a deficient number, since it is larger than the sum of its proper divisors (440841059685).

1011341254443 is a wasteful number, since it uses less digits than its factorization.

1011341254443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25931827053.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 1011341254443 its reverse (3444521431101), we get a palindrome (4455862685544).

The spelling of 1011341254443 in words is "one trillion, eleven billion, three hundred forty-one million, two hundred fifty-four thousand, four hundred forty-three".