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10113525412345 = 559233147137927
BaseRepresentation
bin1001001100101011110100…
…0101101111000111111001
31022210211202222022201210001
42103022331011233013321
52311200000001143340
633302031152353001
72062451405414665
oct223127505570771
938724688281701
1010113525412345
11324a138488653
12117409b245761
13584916b4b824
1426d6d66078a5
151281217b729a
hex932bd16f1f9

10113525412345 has 16 divisors (see below), whose sum is σ = 12394899054720. Its totient is φ = 7919551729024.

The previous prime is 10113525412321. The next prime is 10113525412351. The reversal of 10113525412345 is 54321452531101.

It is a cyclic number.

It is not a de Polignac number, because 10113525412345 - 29 = 10113525411833 is a prime.

It is a super-3 number, since 3×101135254123453 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73500229 + ... + 73637698.

It is an arithmetic number, because the mean of its divisors is an integer number (774681190920).

Almost surely, 210113525412345 is an apocalyptic number.

It is an amenable number.

10113525412345 is a deficient number, since it is larger than the sum of its proper divisors (2281373642375).

10113525412345 is a wasteful number, since it uses less digits than its factorization.

10113525412345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147138224.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 10113525412345 its reverse (54321452531101), we get a palindrome (64434977943446).

The spelling of 10113525412345 in words is "ten trillion, one hundred thirteen billion, five hundred twenty-five million, four hundred twelve thousand, three hundred forty-five".

Divisors: 1 5 59 233 295 1165 13747 68735 147137927 735689635 8681137693 34283136991 43405688465 171415684955 2022705082469 10113525412345