10114114312433 has 8 divisors (see below), whose sum is σ = 10170465477480. Its totient is φ = 10057813758720.

The previous prime is 10114114312391. The next prime is 10114114312447. The reversal of 10114114312433 is 33421341141101.

It can be written as a sum of positive squares in 4 ways, for example, as 9791435782129 + 322678530304 = 3129127^2 + 568048^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10114114312433 - 2⁸ = 10114114312177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10114114312396 and 10114114312405.

It is not an unprimeable number, because it can be changed into a prime (10114114312453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12252008 + ... + 13051433.

It is an arithmetic number, because the mean of its divisors is an integer number (1271308184685).

Almost surely, 2^{10114114312433} is an apocalyptic number.

It is an amenable number.

10114114312433 is a deficient number, since it is larger than the sum of its proper divisors (56351165047).

10114114312433 is a wasteful number, since it uses less digits than its factorization.

10114114312433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25305667.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 10114114312433 its reverse (33421341141101), we get a palindrome (43535455453534).

The spelling of 10114114312433 in words is "ten trillion, one hundred fourteen billion, one hundred fourteen million, three hundred twelve thousand, four hundred thirty-three".