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10114114313003 = 54771846652239
BaseRepresentation
bin1001001100101110000000…
…1100001101101100101011
31022210220022000102222121112
42103023200030031230223
52311202201231004003
633302205430500535
72062502116115351
oct223134014155453
938726260388545
1010114114313003
11324a40a945408
12117422450474b
135849abb5c35c
1426d7509017d1
151281583413d8
hex932e030db2b

10114114313003 has 4 divisors (see below), whose sum is σ = 10115960970720. Its totient is φ = 10112267655288.

The previous prime is 10114114312979. The next prime is 10114114313071. The reversal of 10114114313003 is 30031341141101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10114114313003 - 240 = 9014602685227 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10114114313003.

It is not an unprimeable number, because it can be changed into a prime (10114114313203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 923320643 + ... + 923331596.

It is an arithmetic number, because the mean of its divisors is an integer number (2528990242680).

Almost surely, 210114114313003 is an apocalyptic number.

10114114313003 is a deficient number, since it is larger than the sum of its proper divisors (1846657717).

10114114313003 is an equidigital number, since it uses as much as digits as its factorization.

10114114313003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1846657716.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 10114114313003 its reverse (30031341141101), we get a palindrome (40145455454104).

The spelling of 10114114313003 in words is "ten trillion, one hundred fourteen billion, one hundred fourteen million, three hundred thirteen thousand, three".

Divisors: 1 5477 1846652239 10114114313003