10114300120121 has 4 divisors (see below), whose sum is σ = 10114919923200. Its totient is φ = 10113680317044.

The previous prime is 10114300120069. The next prime is 10114300120139. The reversal of 10114300120121 is 12102100341101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10114300120121 - 2³⁴ = 10097120250937 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10114300120121.

It is not an unprimeable number, because it can be changed into a prime (10114300120721) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 309877061 + ... + 309909698.

It is an arithmetic number, because the mean of its divisors is an integer number (2528729980800).

Almost surely, 2^{10114300120121} is an apocalyptic number.

It is an amenable number.

10114300120121 is a deficient number, since it is larger than the sum of its proper divisors (619803079).

10114300120121 is an equidigital number, since it uses as much as digits as its factorization.

10114300120121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 619803078.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10114300120121 its reverse (12102100341101), we get a palindrome (22216400461222).

The spelling of 10114300120121 in words is "ten trillion, one hundred fourteen billion, three hundred million, one hundred twenty thousand, one hundred twenty-one".