101143131 has 4 divisors (see below), whose sum is σ = 134857512. Its totient is φ = 67428752.

The previous prime is 101143129. The next prime is 101143139. The reversal of 101143131 is 131341101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131341101 = 3 ⋅43780367.

It is a cyclic number.

It is not a de Polignac number, because 101143131 - 2¹ = 101143129 is a prime.

It is a super-2 number, since 2×101143131² = 20459865896966322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101143131.

It is not an unprimeable number, because it can be changed into a prime (101143139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16857186 + ... + 16857191.

It is an arithmetic number, because the mean of its divisors is an integer number (33714378).

Almost surely, 2^101143131 is an apocalyptic number.

101143131 is a deficient number, since it is larger than the sum of its proper divisors (33714381).

101143131 is an equidigital number, since it uses as much as digits as its factorization.

101143131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33714380.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 101143131 is about 10056.9941334377. The cubic root of 101143131 is about 465.9208345444.

Adding to 101143131 its reverse (131341101), we get a palindrome (232484232).

The spelling of 101143131 in words is "one hundred one million, one hundred forty-three thousand, one hundred thirty-one".