Search a number
-
+
10114352121 = 33371450707
BaseRepresentation
bin10010110101101110…
…01100001111111001
3222002212221022202010
421122313030033321
5131203233231441
64351345400133
7505433401026
oct113267141771
928085838663
1010114352121
1143203194a5
121b63339049
13c525b7753
146bd40c54d
153e2e4a116
hex25adcc3f9

10114352121 has 4 divisors (see below), whose sum is σ = 13485802832. Its totient is φ = 6742901412.

The previous prime is 10114352119. The next prime is 10114352177. The reversal of 10114352121 is 12125341101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10114352121 - 21 = 10114352119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10114352191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685725351 + ... + 1685725356.

It is an arithmetic number, because the mean of its divisors is an integer number (3371450708).

Almost surely, 210114352121 is an apocalyptic number.

It is an amenable number.

10114352121 is a deficient number, since it is larger than the sum of its proper divisors (3371450711).

10114352121 is an equidigital number, since it uses as much as digits as its factorization.

10114352121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3371450710.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 10114352121 its reverse (12125341101), we get a palindrome (22239693222).

The spelling of 10114352121 in words is "ten billion, one hundred fourteen million, three hundred fifty-two thousand, one hundred twenty-one".

Divisors: 1 3 3371450707 10114352121