10114433131 has 16 divisors (see below), whose sum is σ = 11372473728. Its totient is φ = 8915572800.

The previous prime is 10114433117. The next prime is 10114433141. The reversal of 10114433131 is 13133441101.

It is a cyclic number.

It is not a de Polignac number, because 10114433131 - 2⁷ = 10114433003 is a prime.

It is a super-2 number, since 2×10114433131² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10114433111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4720 + ... + 142306.

It is an arithmetic number, because the mean of its divisors is an integer number (710779608).

Almost surely, 2^10114433131 is an apocalyptic number.

10114433131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10114433131 is a deficient number, since it is larger than the sum of its proper divisors (1258040597).

10114433131 is a wasteful number, since it uses less digits than its factorization.

10114433131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137802.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10114433131 its reverse (13133441101), we get a palindrome (23247874232).

The spelling of 10114433131 in words is "ten billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred thirty-one".