101150113 has 4 divisors (see below), whose sum is σ = 105547968. Its totient is φ = 96752260.

The previous prime is 101150111. The next prime is 101150123. The reversal of 101150113 is 311051101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 101150113 - 2¹ = 101150111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101150093 and 101150102.

It is not an unprimeable number, because it can be changed into a prime (101150111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198893 + ... + 2198938.

It is an arithmetic number, because the mean of its divisors is an integer number (26386992).

Almost surely, 2^101150113 is an apocalyptic number.

It is an amenable number.

101150113 is a deficient number, since it is larger than the sum of its proper divisors (4397855).

101150113 is an equidigital number, since it uses as much as digits as its factorization.

101150113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4397854.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 101150113 is about 10057.3412490578. The cubic root of 101150113 is about 465.9315552738.

The spelling of 101150113 in words is "one hundred one million, one hundred fifty thousand, one hundred thirteen".