Base | Representation |
---|---|
bin | 1001001100110001100010… |
… | …0101110111010111111011 |
3 | 1022210222201221222101101120 |
4 | 2103030120211313113323 |
5 | 2311211121000431103 |
6 | 33302443352120323 |
7 | 2062534426105140 |
oct | 223143045672773 |
9 | 38728657871346 |
10 | 10115060561403 |
11 | 324a855a95886 |
12 | 11744493960a3 |
13 | 584accbc9655 |
14 | 26d80045a3c7 |
15 | 1281b1456253 |
hex | 933189775fb |
10115060561403 has 8 divisors (see below), whose sum is σ = 15413425617408. Its totient is φ = 5780034606504.
The previous prime is 10115060561393. The next prime is 10115060561407. The reversal of 10115060561403 is 30416506051101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10115060561403 - 24 = 10115060561387 is a prime.
It is a super-3 number, since 3×101150605614033 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (10115060561407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 240834775251 + ... + 240834775292.
It is an arithmetic number, because the mean of its divisors is an integer number (1926678202176).
Almost surely, 210115060561403 is an apocalyptic number.
10115060561403 is a deficient number, since it is larger than the sum of its proper divisors (5298365056005).
10115060561403 is an equidigital number, since it uses as much as digits as its factorization.
10115060561403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 481669550553.
The product of its (nonzero) digits is 10800, while the sum is 33.
The spelling of 10115060561403 in words is "ten trillion, one hundred fifteen billion, sixty million, five hundred sixty-one thousand, four hundred three".
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