1012000320113 has 4 divisors (see below), whose sum is σ = 1014415595760. Its totient is φ = 1009585044468.

The previous prime is 1012000320101. The next prime is 1012000320131. The reversal of 1012000320113 is 3110230002101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1012000320113 - 2¹⁰ = 1012000319089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1012030320113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1207637195 + ... + 1207638032.

It is an arithmetic number, because the mean of its divisors is an integer number (253603898940).

Almost surely, 2^{1012000320113} is an apocalyptic number.

It is an amenable number.

1012000320113 is a deficient number, since it is larger than the sum of its proper divisors (2415275647).

1012000320113 is an equidigital number, since it uses as much as digits as its factorization.

1012000320113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2415275646.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1012000320113 its reverse (3110230002101), we get a palindrome (4122230322214).

The spelling of 1012000320113 in words is "one trillion, twelve billion, three hundred twenty thousand, one hundred thirteen".