10120012000121 has 4 divisors (see below), whose sum is σ = 10214591551632. Its totient is φ = 10025432448612.

The previous prime is 10120012000067. The next prime is 10120012000151. The reversal of 10120012000121 is 12100021002101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10120012000121 is a prime.

It is a super-3 number, since 3×10120012000121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10120012000151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47289775595 + ... + 47289775808.

It is an arithmetic number, because the mean of its divisors is an integer number (2553647887908).

Almost surely, 2^{10120012000121} is an apocalyptic number.

It is an amenable number.

10120012000121 is a deficient number, since it is larger than the sum of its proper divisors (94579551511).

10120012000121 is an equidigital number, since it uses as much as digits as its factorization.

10120012000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94579551510.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10120012000121 its reverse (12100021002101), we get a palindrome (22220033002222).

The spelling of 10120012000121 in words is "ten trillion, one hundred twenty billion, twelve million, one hundred twenty-one", and thus it is an aban number.