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1012011130131 = 3393678569031
BaseRepresentation
bin11101011101000001001…
…00000101110100010011
310120202011210111001111120
432232200210011310103
5113040044322131011
62052524514413323
7133054402450101
oct16564044056423
93522153431446
101012011130131
11360211999821
12144174591243
1374580829431
1436da5720c71
151b4d0e84a06
hexeba0905d13

1012011130131 has 8 divisors (see below), whose sum is σ = 1349382607104. Its totient is φ = 674656869960.

The previous prime is 1012011130093. The next prime is 1012011130153. The reversal of 1012011130131 is 1310311102101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1012011130131 - 213 = 1012011121939 is a prime.

It is a super-2 number, since 2×10120111301312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1012011130131.

It is not an unprimeable number, because it can be changed into a prime (1012011130181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4166415 + ... + 4402616.

It is an arithmetic number, because the mean of its divisors is an integer number (168672825888).

Almost surely, 21012011130131 is an apocalyptic number.

1012011130131 is a deficient number, since it is larger than the sum of its proper divisors (337371476973).

1012011130131 is an equidigital number, since it uses as much as digits as its factorization.

1012011130131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8608401.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 1012011130131 its reverse (1310311102101), we get a palindrome (2322322232232).

The spelling of 1012011130131 in words is "one trillion, twelve billion, eleven million, one hundred thirty thousand, one hundred thirty-one".

Divisors: 1 3 39367 118101 8569031 25707093 337337043377 1012011130131