Base | Representation |
---|---|
bin | 10111000000101010111111… |
… | …100110101010101101001011 |
3 | 111021022202002000000222212110 |
4 | 113000222333212222231023 |
5 | 101231040111401404003 |
6 | 555123112144313403 |
7 | 30213355630604655 |
oct | 2700527746525513 |
9 | 437282060028773 |
10 | 101201234013003 |
11 | 2a278225320523 |
12 | b425588612863 |
13 | 446130a2a3857 |
14 | 1adc2471a16d5 |
15 | ba77229b3a03 |
hex | 5c0abf9aab4b |
101201234013003 has 16 divisors (see below), whose sum is σ = 135035114704640. Its totient is φ = 67417426337184.
The previous prime is 101201234012971. The next prime is 101201234013083. The reversal of 101201234013003 is 300310432102101.
It is not a de Polignac number, because 101201234013003 - 25 = 101201234012971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101201234013083) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81590850 + ... + 82821912.
It is an arithmetic number, because the mean of its divisors is an integer number (8439694669040).
Almost surely, 2101201234013003 is an apocalyptic number.
101201234013003 is a deficient number, since it is larger than the sum of its proper divisors (33833880691637).
101201234013003 is a wasteful number, since it uses less digits than its factorization.
101201234013003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1251378.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 101201234013003 its reverse (300310432102101), we get a palindrome (401511666115104).
The spelling of 101201234013003 in words is "one hundred one trillion, two hundred one billion, two hundred thirty-four million, thirteen thousand, three".
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