Base | Representation |
---|---|
bin | 101111001000000010… |
… | …0011100001110101001 |
3 | 100200012220011021201122 |
4 | 1132100010130032221 |
5 | 3124230020043423 |
6 | 114254035425025 |
7 | 10211602056401 |
oct | 1362004341651 |
9 | 320186137648 |
10 | 101201331113 |
11 | 39a12570a33 |
12 | 17744155175 |
13 | 970a67ba5c |
14 | 4c80819801 |
15 | 29749398c8 |
hex | 179011c3a9 |
101201331113 has 8 divisors (see below), whose sum is σ = 102180538368. Its totient is φ = 100223591104.
The previous prime is 101201331103. The next prime is 101201331167. The reversal of 101201331113 is 311133102101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 101201331113 - 24 = 101201331097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 101201331091 and 101201331100.
It is not an unprimeable number, because it can be changed into a prime (101201331103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227945 + ... + 504342.
It is an arithmetic number, because the mean of its divisors is an integer number (12772567296).
Almost surely, 2101201331113 is an apocalyptic number.
It is an amenable number.
101201331113 is a deficient number, since it is larger than the sum of its proper divisors (979207255).
101201331113 is a wasteful number, since it uses less digits than its factorization.
101201331113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 733623.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 101201331113 its reverse (311133102101), we get a palindrome (412334433214).
The spelling of 101201331113 in words is "one hundred one billion, two hundred one million, three hundred thirty-one thousand, one hundred thirteen".
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