10120203221131 has 4 divisors (see below), whose sum is σ = 10120351620712. Its totient is φ = 10120054821552.

The previous prime is 10120203221071. The next prime is 10120203221159. The reversal of 10120203221131 is 13112230202101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10120203221131 - 2¹³ = 10120203212939 is a prime.

It is a super-2 number, since 2×10120203221131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10120203221099 and 10120203221108.

It is not an unprimeable number, because it can be changed into a prime (10120203221171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74097450 + ... + 74233903.

It is an arithmetic number, because the mean of its divisors is an integer number (2530087905178).

Almost surely, 2^{10120203221131} is an apocalyptic number.

10120203221131 is a deficient number, since it is larger than the sum of its proper divisors (148399581).

10120203221131 is an equidigital number, since it uses as much as digits as its factorization.

10120203221131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148399580.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10120203221131 its reverse (13112230202101), we get a palindrome (23232433423232).

The spelling of 10120203221131 in words is "ten trillion, one hundred twenty billion, two hundred three million, two hundred twenty-one thousand, one hundred thirty-one".