10120221313 has 4 divisors (see below), whose sum is σ = 10652864560. Its totient is φ = 9587578068.

The previous prime is 10120221299. The next prime is 10120221383. The reversal of 10120221313 is 31312202101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10120221313 - 2¹³ = 10120213121 is a prime.

It is a super-3 number, since 3×10120221313³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10120221383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266321595 + ... + 266321632.

It is an arithmetic number, because the mean of its divisors is an integer number (2663216140).

Almost surely, 2^10120221313 is an apocalyptic number.

It is an amenable number.

10120221313 is a deficient number, since it is larger than the sum of its proper divisors (532643247).

10120221313 is an equidigital number, since it uses as much as digits as its factorization.

10120221313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 532643246.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10120221313 its reverse (31312202101), we get a palindrome (41432423414).

The spelling of 10120221313 in words is "ten billion, one hundred twenty million, two hundred twenty-one thousand, three hundred thirteen".