Search a number
-
+
1012044342433 = 1953265491707
BaseRepresentation
bin11101011101000101000…
…10110010010010100001
310120202021002222102012211
432232202202302102201
5113040131322424213
62052532102322121
7133055254655005
oct16564242622241
93522232872184
101012044342433
11360229713703
12144183729341
1374587687597
1436da9cc8705
151b4d3d4553d
hexeba28b24a1

1012044342433 has 4 divisors (see below), whose sum is σ = 1065309834160. Its totient is φ = 958778850708.

The previous prime is 1012044342389. The next prime is 1012044342481. The reversal of 1012044342433 is 3342434402101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1012044342433 - 237 = 874605388961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012044342395 and 1012044342404.

It is not an unprimeable number, because it can be changed into a prime (1012044342493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26632745835 + ... + 26632745872.

It is an arithmetic number, because the mean of its divisors is an integer number (266327458540).

Almost surely, 21012044342433 is an apocalyptic number.

It is an amenable number.

1012044342433 is a deficient number, since it is larger than the sum of its proper divisors (53265491727).

1012044342433 is an equidigital number, since it uses as much as digits as its factorization.

1012044342433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53265491726.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1012044342433 its reverse (3342434402101), we get a palindrome (4354478744534).

The spelling of 1012044342433 in words is "one trillion, twelve billion, forty-four million, three hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 19 53265491707 1012044342433