101209999963 has 4 divisors (see below), whose sum is σ = 105610434768. Its totient is φ = 96809565160.

The previous prime is 101209999939. The next prime is 101209999997. The reversal of 101209999963 is 369999902101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 369999902101 = 53117 ⋅6965753.

It is a cyclic number.

It is not a de Polignac number, because 101209999963 - 2²¹ = 101207902811 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101209999898 and 101209999907.

It is not an unprimeable number, because it can be changed into a prime (101209996963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200217368 + ... + 2200217413.

It is an arithmetic number, because the mean of its divisors is an integer number (26402608692).

Almost surely, 2^101209999963 is an apocalyptic number.

101209999963 is a deficient number, since it is larger than the sum of its proper divisors (4400434805).

101209999963 is an equidigital number, since it uses as much as digits as its factorization.

101209999963 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4400434804.

The product of its (nonzero) digits is 2125764, while the sum is 58.

The spelling of 101209999963 in words is "one hundred one billion, two hundred nine million, nine hundred ninety-nine thousand, nine hundred sixty-three".