10121111113 has 4 divisors (see below), whose sum is σ = 10138179348. Its totient is φ = 10104042880.

The previous prime is 10121111101. The next prime is 10121111191. The reversal of 10121111113 is 31111112101.

10121111113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5540122624 + 4580988489 = 74432^2 + 67683^2 .

It is a cyclic number.

It is not a de Polignac number, because 10121111113 - 2⁵ = 10121111081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10121111093 and 10121111102.

It is not an unprimeable number, because it can be changed into a prime (10121111813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8533228 + ... + 8534413.

It is an arithmetic number, because the mean of its divisors is an integer number (2534544837).

Almost surely, 2^10121111113 is an apocalyptic number.

It is an amenable number.

10121111113 is a deficient number, since it is larger than the sum of its proper divisors (17068235).

10121111113 is an equidigital number, since it uses as much as digits as its factorization.

10121111113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17068234.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 10121111113 its reverse (31111112101), we get a palindrome (41232223214).

The spelling of 10121111113 in words is "ten billion, one hundred twenty-one million, one hundred eleven thousand, one hundred thirteen".