101213041211433 has 16 divisors (see below), whose sum is σ = 153997820463360. Its totient is φ = 65651702406768.

The previous prime is 101213041211423. The next prime is 101213041211479. The reversal of 101213041211433 is 334112140312101.

101213041211433 is a `hidden beast` number, since 1 + 0 + 1 + 2 + 13 + 0 + 4 + 1 + 211 + 433 = 666.

It is not a de Polignac number, because 101213041211433 - 2⁴ = 101213041211417 is a prime.

It is a super-2 number, since 2×101213041211433² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101213041211397 and 101213041211406.

It is not an unprimeable number, because it can be changed into a prime (101213041211413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50657176785 + ... + 50657178782.

It is an arithmetic number, because the mean of its divisors is an integer number (9624863778960).

Almost surely, 2^{101213041211433} is an apocalyptic number.

It is an amenable number.

101213041211433 is a deficient number, since it is larger than the sum of its proper divisors (52784779251927).

101213041211433 is a wasteful number, since it uses less digits than its factorization.

101213041211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101314355613 (or 101314355607 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 101213041211433 its reverse (334112140312101), we get a palindrome (435325181523534).

The spelling of 101213041211433 in words is "one hundred one trillion, two hundred thirteen billion, forty-one million, two hundred eleven thousand, four hundred thirty-three".