10122123113 has 4 divisors (see below), whose sum is σ = 10123597200. Its totient is φ = 10120649028.

The previous prime is 10122123079. The next prime is 10122123127. The reversal of 10122123113 is 31132122101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10122123113 - 2¹² = 10122119017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10122123091 and 10122123100.

It is not an unprimeable number, because it can be changed into a prime (10122123163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 726695 + ... + 740492.

It is an arithmetic number, because the mean of its divisors is an integer number (2530899300).

Almost surely, 2^10122123113 is an apocalyptic number.

It is an amenable number.

10122123113 is a deficient number, since it is larger than the sum of its proper divisors (1474087).

10122123113 is an equidigital number, since it uses as much as digits as its factorization.

10122123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1474086.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10122123113 its reverse (31132122101), we get a palindrome (41254245214).

The spelling of 10122123113 in words is "ten billion, one hundred twenty-two million, one hundred twenty-three thousand, one hundred thirteen".