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10122303433 = 11920209403
BaseRepresentation
bin10010110110101011…
…00001011111001001
3222010102220021220011
421123111201133021
5131212302202213
64352232031521
7505561105504
oct113325413711
928112807804
1010122303433
11432485a430
121b65b325a1
13c5413c978
146c04bc13b
153e39bb03d
hex25b5617c9

10122303433 has 4 divisors (see below), whose sum is σ = 11042512848. Its totient is φ = 9202094020.

The previous prime is 10122303431. The next prime is 10122303439. The reversal of 10122303433 is 33430322101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10122303433 - 21 = 10122303431 is a prime.

It is a super-2 number, since 2×101223034332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10122303431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 460104691 + ... + 460104712.

It is an arithmetic number, because the mean of its divisors is an integer number (2760628212).

Almost surely, 210122303433 is an apocalyptic number.

It is an amenable number.

10122303433 is a deficient number, since it is larger than the sum of its proper divisors (920209415).

10122303433 is an equidigital number, since it uses as much as digits as its factorization.

10122303433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 920209414.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 10122303433 its reverse (33430322101), we get a palindrome (43552625534).

The spelling of 10122303433 in words is "ten billion, one hundred twenty-two million, three hundred three thousand, four hundred thirty-three".

Divisors: 1 11 920209403 10122303433