10123230113 has 4 divisors (see below), whose sum is σ = 10181746068. Its totient is φ = 10064714160.

The previous prime is 10123230083. The next prime is 10123230149. The reversal of 10123230113 is 31103232101.

10123230113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31103232101 = 72461 ⋅429241.

It can be written as a sum of positive squares in 2 ways, for example, as 7319315809 + 2803914304 = 85553^2 + 52952^2 .

It is a cyclic number.

It is not a de Polignac number, because 10123230113 - 2²² = 10119035809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10123230091 and 10123230100.

It is not an unprimeable number, because it can be changed into a prime (10123232113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29257718 + ... + 29258063.

It is an arithmetic number, because the mean of its divisors is an integer number (2545436517).

Almost surely, 2^10123230113 is an apocalyptic number.

It is an amenable number.

10123230113 is a deficient number, since it is larger than the sum of its proper divisors (58515955).

10123230113 is an equidigital number, since it uses as much as digits as its factorization.

10123230113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58515954.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10123230113 its reverse (31103232101), we get a palindrome (41226462214).

The spelling of 10123230113 in words is "ten billion, one hundred twenty-three million, two hundred thirty thousand, one hundred thirteen".