101233121313001 has 4 divisors (see below), whose sum is σ = 105634561370112. Its totient is φ = 96831681255892.

The previous prime is 101233121312969. The next prime is 101233121313013. The reversal of 101233121313001 is 100313121332101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101233121313001 - 2⁵ = 101233121312969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101233121313061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200720028521 + ... + 2200720028566.

It is an arithmetic number, because the mean of its divisors is an integer number (26408640342528).

Almost surely, 2^{101233121313001} is an apocalyptic number.

It is an amenable number.

101233121313001 is a deficient number, since it is larger than the sum of its proper divisors (4401440057111).

101233121313001 is an equidigital number, since it uses as much as digits as its factorization.

101233121313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4401440057110.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 101233121313001 its reverse (100313121332101), we get a palindrome (201546242645102).

The spelling of 101233121313001 in words is "one hundred one trillion, two hundred thirty-three billion, one hundred twenty-one million, three hundred thirteen thousand, one".