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10123333113 = 33374444371
BaseRepresentation
bin10010110110110010…
…11100110111111001
3222010111211121100110
421123121130313321
5131213033124423
64352310054533
7505602624465
oct113331346771
928114747313
1010123333113
1143253a3003
121b6634a449
13c5441054a
146c06a94a5
153e3b21193
hex25b65cdf9

10123333113 has 4 divisors (see below), whose sum is σ = 13497777488. Its totient is φ = 6748888740.

The previous prime is 10123333069. The next prime is 10123333139. The reversal of 10123333113 is 31133332101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10123333113 - 212 = 10123329017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10123333113.

It is not an unprimeable number, because it can be changed into a prime (10123333813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1687222183 + ... + 1687222188.

It is an arithmetic number, because the mean of its divisors is an integer number (3374444372).

Almost surely, 210123333113 is an apocalyptic number.

It is an amenable number.

10123333113 is a deficient number, since it is larger than the sum of its proper divisors (3374444375).

10123333113 is an equidigital number, since it uses as much as digits as its factorization.

10123333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3374444374.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 10123333113 its reverse (31133332101), we get a palindrome (41256665214).

The spelling of 10123333113 in words is "ten billion, one hundred twenty-three million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 3374444371 10123333113