10123443321403 has 4 divisors (see below), whose sum is σ = 10123449774480. Its totient is φ = 10123436868328.

The previous prime is 10123443321401. The next prime is 10123443321413. The reversal of 10123443321403 is 30412334432101.

10123443321403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10123443321403 - 2¹ = 10123443321401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10123443321401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809538 + ... + 4571896.

It is an arithmetic number, because the mean of its divisors is an integer number (2530862443620).

Almost surely, 2^{10123443321403} is an apocalyptic number.

10123443321403 is a deficient number, since it is larger than the sum of its proper divisors (6453077).

10123443321403 is an equidigital number, since it uses as much as digits as its factorization.

10123443321403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6453076.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 10123443321403 its reverse (30412334432101), we get a palindrome (40535777753504).

The spelling of 10123443321403 in words is "ten trillion, one hundred twenty-three billion, four hundred forty-three million, three hundred twenty-one thousand, four hundred three".