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10125000451 = 12779724413
BaseRepresentation
bin10010110110111111…
…10011111100000011
3222010121222022111201
421123133303330003
5131214000003301
64352405522031
7505623040516
oct113337637403
928117868451
1010125000451
114326331775
121b66a13317
13c54875437
146c09c0d7d
153e3d50201
hex25b7f3f03

10125000451 has 4 divisors (see below), whose sum is σ = 10204724992. Its totient is φ = 10045275912.

The previous prime is 10125000439. The next prime is 10125000467. The reversal of 10125000451 is 15400052101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10125000451 - 217 = 10124869379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10125000491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39862080 + ... + 39862333.

It is an arithmetic number, because the mean of its divisors is an integer number (2551181248).

Almost surely, 210125000451 is an apocalyptic number.

10125000451 is a deficient number, since it is larger than the sum of its proper divisors (79724541).

10125000451 is an equidigital number, since it uses as much as digits as its factorization.

10125000451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79724540.

The product of its (nonzero) digits is 200, while the sum is 19.

Adding to 10125000451 its reverse (15400052101), we get a palindrome (25525052552).

The spelling of 10125000451 in words is "ten billion, one hundred twenty-five million, four hundred fifty-one", and thus it is an aban number.

Divisors: 1 127 79724413 10125000451