Base | Representation |
---|---|
bin | 10111000001110101001000… |
… | …011001111010110100011011 |
3 | 111021121100112210001000202211 |
4 | 113001311020121322310123 |
5 | 101233341124132423201 |
6 | 555223435214135551 |
7 | 30222204411236302 |
oct | 2701651031726433 |
9 | 437540483030684 |
10 | 101280838561051 |
11 | 2a2a8a64a88706 |
12 | b438aa3ab15b7 |
13 | 44689854ca216 |
14 | 1b020395db439 |
15 | ba98313bb651 |
hex | 5c1d4867ad1b |
101280838561051 has 4 divisors (see below), whose sum is σ = 101552368959712. Its totient is φ = 101009308162392.
The previous prime is 101280838561043. The next prime is 101280838561057. The reversal of 101280838561051 is 150165838082101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101280838561051 - 23 = 101280838561043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 101280838560986 and 101280838561004.
It is not an unprimeable number, because it can be changed into a prime (101280838561057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135765198771 + ... + 135765199516.
It is an arithmetic number, because the mean of its divisors is an integer number (25388092239928).
Almost surely, 2101280838561051 is an apocalyptic number.
101280838561051 is a deficient number, since it is larger than the sum of its proper divisors (271530398661).
101280838561051 is an equidigital number, since it uses as much as digits as its factorization.
101280838561051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 271530398660.
The product of its (nonzero) digits is 460800, while the sum is 49.
The spelling of 101280838561051 in words is "one hundred one trillion, two hundred eighty billion, eight hundred thirty-eight million, five hundred sixty-one thousand, fifty-one".
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