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10130001332011 = 112931755490069
BaseRepresentation
bin1001001101101001001100…
…1000011000011100101011
31022212102022012200011121221
42103122103020120130223
52311432220320111021
633313354112442511
72063603606420131
oct223322310303453
938772265604557
1010130001332011
113256122732990
121177318b49437
135863413a8412
1427041a863751
15128787e6b241
hex9369321872b

10130001332011 has 8 divisors (see below), whose sum is σ = 11431976425200. Its totient is φ = 8891537219040.

The previous prime is 10130001331997. The next prime is 10130001332041. The reversal of 10130001332011 is 11023310003101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10130001332011 - 211 = 10130001329963 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10130001332041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15877744716 + ... + 15877745353.

It is an arithmetic number, because the mean of its divisors is an integer number (1428997053150).

Almost surely, 210130001332011 is an apocalyptic number.

10130001332011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10130001332011 is a deficient number, since it is larger than the sum of its proper divisors (1301975093189).

10130001332011 is a wasteful number, since it uses less digits than its factorization.

10130001332011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31755490109.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10130001332011 its reverse (11023310003101), we get a palindrome (21153311335112).

The spelling of 10130001332011 in words is "ten trillion, one hundred thirty billion, one million, three hundred thirty-two thousand, eleven".

Divisors: 1 11 29 319 31755490069 349310390759 920909212001 10130001332011