101301130033 has 4 divisors (see below), whose sum is σ = 101301771760. Its totient is φ = 101300488308.

The previous prime is 101301130003. The next prime is 101301130087. The reversal of 101301130033 is 330031103101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 101301130033 - 2⁹ = 101301129521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101301129989 and 101301130016.

It is not an unprimeable number, because it can be changed into a prime (101301130003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99466 + ... + 460972.

It is an arithmetic number, because the mean of its divisors is an integer number (25325442940).

Almost surely, 2^101301130033 is an apocalyptic number.

It is an amenable number.

101301130033 is a deficient number, since it is larger than the sum of its proper divisors (641727).

101301130033 is an equidigital number, since it uses as much as digits as its factorization.

101301130033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 641726.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 101301130033 its reverse (330031103101), we get a palindrome (431332233134).

The spelling of 101301130033 in words is "one hundred one billion, three hundred one million, one hundred thirty thousand, thirty-three".