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10130213433 = 34577388923
BaseRepresentation
bin10010110111100111…
…01100101000111001
3222010222210011101010
421123303230220321
5131221313312213
64353113344133
7506015251644
oct113363545071
928128704333
1010130213433
11432927231a
121b68708049
13c5597c142
146c157aa5b
153e452eac3
hex25bceca39

10130213433 has 8 divisors (see below), whose sum is σ = 13536508768. Its totient is φ = 6738696864.

The previous prime is 10130213417. The next prime is 10130213441. The reversal of 10130213433 is 33431203101.

10130213433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10130213433 - 24 = 10130213417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10130214433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3693091 + ... + 3695832.

It is an arithmetic number, because the mean of its divisors is an integer number (1692063596).

Almost surely, 210130213433 is an apocalyptic number.

It is an amenable number.

10130213433 is a deficient number, since it is larger than the sum of its proper divisors (3406295335).

10130213433 is an equidigital number, since it uses as much as digits as its factorization.

10130213433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7389383.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 10130213433 its reverse (33431203101), we get a palindrome (43561416534).

The spelling of 10130213433 in words is "ten billion, one hundred thirty million, two hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 3 457 1371 7388923 22166769 3376737811 10130213433