1013040213001 has 4 divisors (see below), whose sum is σ = 1017243699604. Its totient is φ = 1008836726400.

The previous prime is 1013040212963. The next prime is 1013040213011. The reversal of 1013040213001 is 1003120403101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 903678384400 + 109361828601 = 950620^2 + 330699^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013040213001 - 2¹⁵ = 1013040180233 is a prime.

It is a super-2 number, since 2×1013040213001² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1013040213011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2101742940 + ... + 2101743421.

It is an arithmetic number, because the mean of its divisors is an integer number (254310924901).

Almost surely, 2^{1013040213001} is an apocalyptic number.

It is an amenable number.

1013040213001 is a deficient number, since it is larger than the sum of its proper divisors (4203486603).

1013040213001 is an equidigital number, since it uses as much as digits as its factorization.

1013040213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4203486602.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1013040213001 its reverse (1003120403101), we get a palindrome (2016160616102).

The spelling of 1013040213001 in words is "one trillion, thirteen billion, forty million, two hundred thirteen thousand, one".