10130413433 has 8 divisors (see below), whose sum is σ = 11605925760. Its totient is φ = 8661978720.

The previous prime is 10130413421. The next prime is 10130413459. The reversal of 10130413433 is 33431403101.

10130413433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10130413433 - 2¹² = 10130409337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10130413399 and 10130413408.

It is not an unprimeable number, because it can be changed into a prime (10130413633) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1766333 + ... + 1772058.

It is an arithmetic number, because the mean of its divisors is an integer number (1450740720).

Almost surely, 2^10130413433 is an apocalyptic number.

It is an amenable number.

10130413433 is a deficient number, since it is larger than the sum of its proper divisors (1475512327).

10130413433 is an equidigital number, since it uses as much as digits as its factorization.

10130413433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3538807.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10130413433 its reverse (33431403101), we get a palindrome (43561816534).

The spelling of 10130413433 in words is "ten billion, one hundred thirty million, four hundred thirteen thousand, four hundred thirty-three".