10131030133113 has 4 divisors (see below), whose sum is σ = 13508040177488. Its totient is φ = 6754020088740.

The previous prime is 10131030133109. The next prime is 10131030133117. The reversal of 10131030133113 is 31133103013101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10131030133109) and next prime (10131030133117).

It is not a de Polignac number, because 10131030133113 - 2² = 10131030133109 is a prime.

It is a super-2 number, since 2×10131030133113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10131030133113.

It is not an unprimeable number, because it can be changed into a prime (10131030133117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1688505022183 + ... + 1688505022188.

It is an arithmetic number, because the mean of its divisors is an integer number (3377010044372).

Almost surely, 2^{10131030133113} is an apocalyptic number.

It is an amenable number.

10131030133113 is a deficient number, since it is larger than the sum of its proper divisors (3377010044375).

10131030133113 is an equidigital number, since it uses as much as digits as its factorization.

10131030133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3377010044374.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 10131030133113 its reverse (31133103013101), we get a palindrome (41264133146214).

The spelling of 10131030133113 in words is "ten trillion, one hundred thirty-one billion, thirty million, one hundred thirty-three thousand, one hundred thirteen".