Base | Representation |
---|---|
bin | 1001001101101101000001… |
… | …1100111100100101111011 |
3 | 1022212111221220112200102112 |
4 | 2103123100130330211323 |
5 | 2311441322203224430 |
6 | 33314044143322535 |
7 | 2063641241164223 |
oct | 223332034744573 |
9 | 38774856480375 |
10 | 10131030133115 |
11 | 3256600438431 |
12 | 11775655b044b |
13 | 58647658a978 |
14 | 2704b734b083 |
15 | 1287e843b195 |
hex | 936d073c97b |
10131030133115 has 8 divisors (see below), whose sum is σ = 12685811645088. Its totient is φ = 7752440449600.
The previous prime is 10131030133109. The next prime is 10131030133117. The reversal of 10131030133115 is 51133103013101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10131030133115 - 24 = 10131030133099 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10131030133117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44047956986 + ... + 44047957215.
It is an arithmetic number, because the mean of its divisors is an integer number (1585726455636).
Almost surely, 210131030133115 is an apocalyptic number.
10131030133115 is a deficient number, since it is larger than the sum of its proper divisors (2554781511973).
10131030133115 is an equidigital number, since it uses as much as digits as its factorization.
10131030133115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88095914229.
The product of its (nonzero) digits is 405, while the sum is 23.
Adding to 10131030133115 its reverse (51133103013101), we get a palindrome (61264133146216).
The spelling of 10131030133115 in words is "ten trillion, one hundred thirty-one billion, thirty million, one hundred thirty-three thousand, one hundred fifteen".
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