1013103414433 has 4 divisors (see below), whose sum is σ = 1105203724848. Its totient is φ = 921003104020.

The previous prime is 1013103414419. The next prime is 1013103414451. The reversal of 1013103414433 is 3344143013101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1013103414433 - 2⁹ = 1013103413921 is a prime.

It is a super-2 number, since 2×1013103414433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1013103418433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46050155191 + ... + 46050155212.

It is an arithmetic number, because the mean of its divisors is an integer number (276300931212).

Almost surely, 2^{1013103414433} is an apocalyptic number.

It is an amenable number.

1013103414433 is a deficient number, since it is larger than the sum of its proper divisors (92100310415).

1013103414433 is an equidigital number, since it uses as much as digits as its factorization.

1013103414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92100310414.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1013103414433 its reverse (3344143013101), we get a palindrome (4357246427534).

The spelling of 1013103414433 in words is "one trillion, thirteen billion, one hundred three million, four hundred fourteen thousand, four hundred thirty-three".