10131330113 has 4 divisors (see below), whose sum is σ = 10204217520. Its totient is φ = 10058442708.

The previous prime is 10131330109. The next prime is 10131330151. The reversal of 10131330113 is 31103313101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10131330113 - 2² = 10131330109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10131330091 and 10131330100.

It is not an unprimeable number, because it can be changed into a prime (10131330163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36443495 + ... + 36443772.

It is an arithmetic number, because the mean of its divisors is an integer number (2551054380).

Almost surely, 2^10131330113 is an apocalyptic number.

It is an amenable number.

10131330113 is a deficient number, since it is larger than the sum of its proper divisors (72887407).

10131330113 is an equidigital number, since it uses as much as digits as its factorization.

10131330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72887406.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10131330113 its reverse (31103313101), we get a palindrome (41234643214).

The spelling of 10131330113 in words is "ten billion, one hundred thirty-one million, three hundred thirty thousand, one hundred thirteen".