Base | Representation |
---|---|
bin | 10010110111110101… |
… | …11001100100111001 |
3 | 222011010100002020001 |
4 | 21123322321210321 |
5 | 131222304221213 |
6 | 4353222033001 |
7 | 506040304216 |
oct | 113372714471 |
9 | 28133302201 |
10 | 10132101433 |
11 | 432a341853 |
12 | 1b69278761 |
13 | c561905bc |
14 | 6c190cb0d |
15 | 3e47a41dd |
hex | 25beb9939 |
10132101433 has 4 divisors (see below), whose sum is σ = 10135456128. Its totient is φ = 10128746740.
The previous prime is 10132101409. The next prime is 10132101437. The reversal of 10132101433 is 33410123101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10132101433 - 25 = 10132101401 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10132101433.
It is not an unprimeable number, because it can be changed into a prime (10132101437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672813 + ... + 1678858.
It is an arithmetic number, because the mean of its divisors is an integer number (2533864032).
Almost surely, 210132101433 is an apocalyptic number.
It is an amenable number.
10132101433 is a deficient number, since it is larger than the sum of its proper divisors (3354695).
10132101433 is an equidigital number, since it uses as much as digits as its factorization.
10132101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3354694.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 10132101433 its reverse (33410123101), we get a palindrome (43542224534).
The spelling of 10132101433 in words is "ten billion, one hundred thirty-two million, one hundred one thousand, four hundred thirty-three".
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