10132431113 has 4 divisors (see below), whose sum is σ = 11579921280. Its totient is φ = 8684940948.

The previous prime is 10132431097. The next prime is 10132431187. The reversal of 10132431113 is 31113423101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31113423101 = 36713 ⋅847477.

It is a cyclic number.

It is not a de Polignac number, because 10132431113 - 2⁴ = 10132431097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10132434113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723745073 + ... + 723745086.

It is an arithmetic number, because the mean of its divisors is an integer number (2894980320).

Almost surely, 2^10132431113 is an apocalyptic number.

It is an amenable number.

10132431113 is a deficient number, since it is larger than the sum of its proper divisors (1447490167).

10132431113 is an equidigital number, since it uses as much as digits as its factorization.

10132431113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1447490166.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 10132431113 its reverse (31113423101), we get a palindrome (41245854214).

The spelling of 10132431113 in words is "ten billion, one hundred thirty-two million, four hundred thirty-one thousand, one hundred thirteen".