10133112101131 has 4 divisors (see below), whose sum is σ = 10176601852872. Its totient is φ = 10089622349392.

The previous prime is 10133112101093. The next prime is 10133112101137. The reversal of 10133112101131 is 13110121133101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10133112101131 - 2⁷ = 10133112101003 is a prime.

It is a super-2 number, since 2×10133112101131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10133112101099 and 10133112101108.

It is not an unprimeable number, because it can be changed into a prime (10133112101137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21744875521 + ... + 21744875986.

It is an arithmetic number, because the mean of its divisors is an integer number (2544150463218).

Almost surely, 2^{10133112101131} is an apocalyptic number.

10133112101131 is a deficient number, since it is larger than the sum of its proper divisors (43489751741).

10133112101131 is an equidigital number, since it uses as much as digits as its factorization.

10133112101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43489751740.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10133112101131 its reverse (13110121133101), we get a palindrome (23243233234232).

The spelling of 10133112101131 in words is "ten trillion, one hundred thirty-three billion, one hundred twelve million, one hundred one thousand, one hundred thirty-one".