Base | Representation |
---|---|
bin | 10010110111111110… |
… | …01000100011000011 |
3 | 222011012102110201101 |
4 | 21123333020203003 |
5 | 131223100230311 |
6 | 4353301515231 |
7 | 506052606115 |
oct | 113377104303 |
9 | 28135373641 |
10 | 10133211331 |
11 | 432aa2a721 |
12 | 1b69712b17 |
13 | c5648b849 |
14 | 6c1b1b3b5 |
15 | 3e4922ec1 |
hex | 25bfc88c3 |
10133211331 has 4 divisors (see below), whose sum is σ = 10134035064. Its totient is φ = 10132387600.
The previous prime is 10133211329. The next prime is 10133211419. The reversal of 10133211331 is 13311233101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10133211331 - 21 = 10133211329 is a prime.
It is a super-2 number, since 2×101332113312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10133211299 and 10133211308.
It is not an unprimeable number, because it can be changed into a prime (10133211031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393130 + ... + 418111.
It is an arithmetic number, because the mean of its divisors is an integer number (2533508766).
Almost surely, 210133211331 is an apocalyptic number.
10133211331 is a deficient number, since it is larger than the sum of its proper divisors (823733).
10133211331 is an equidigital number, since it uses as much as digits as its factorization.
10133211331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 823732.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 10133211331 its reverse (13311233101), we get a palindrome (23444444432).
The spelling of 10133211331 in words is "ten billion, one hundred thirty-three million, two hundred eleven thousand, three hundred thirty-one".
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