101333113 has 4 divisors (see below), whose sum is σ = 115809280. Its totient is φ = 86856948.

The previous prime is 101333083. The next prime is 101333119. The reversal of 101333113 is 311333101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311333101 = 73 ⋅4264837.

It is a cyclic number.

It is not a de Polignac number, because 101333113 - 2¹⁷ = 101202041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101333119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7238073 + ... + 7238086.

It is an arithmetic number, because the mean of its divisors is an integer number (28952320).

Almost surely, 2^101333113 is an apocalyptic number.

It is an amenable number.

101333113 is a deficient number, since it is larger than the sum of its proper divisors (14476167).

101333113 is an equidigital number, since it uses as much as digits as its factorization.

101333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14476166.

The product of its (nonzero) digits is 81, while the sum is 16.

The square root of 101333113 is about 10066.4349697398. The cubic root of 101333113 is about 466.2123725765.

Adding to 101333113 its reverse (311333101), we get a palindrome (412666214).

The spelling of 101333113 in words is "one hundred one million, three hundred thirty-three thousand, one hundred thirteen".