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101333121113 = 749929010341
BaseRepresentation
bin101111001011111101…
…1001011100001011001
3100200120002010220121202
41132113323023201121
53130012234333423
6114315104243545
710215062213660
oct1362773134131
9320502126552
10101333121113
1139a7a9a5794
12177803105b5
13972ba731c3
144c94123dd7
1529812bd728
hex1797ecb859

101333121113 has 8 divisors (see below), whose sum is σ = 116041368000. Its totient is φ = 86682895920.

The previous prime is 101333121107. The next prime is 101333121119. The reversal of 101333121113 is 311121333101.

It is an interprime number because it is at equal distance from previous prime (101333121107) and next prime (101333121119).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101333121113 - 218 = 101332858969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101333121119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14501678 + ... + 14508663.

It is an arithmetic number, because the mean of its divisors is an integer number (14505171000).

Almost surely, 2101333121113 is an apocalyptic number.

It is an amenable number.

101333121113 is a deficient number, since it is larger than the sum of its proper divisors (14708246887).

101333121113 is an equidigital number, since it uses as much as digits as its factorization.

101333121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29010847.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 101333121113 its reverse (311121333101), we get a palindrome (412454454214).

The spelling of 101333121113 in words is "one hundred one billion, three hundred thirty-three million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 7 499 3493 29010341 203072387 14476160159 101333121113