Base | Representation |
---|---|
bin | 101111001011111101… |
… | …1001011100001011001 |
3 | 100200120002010220121202 |
4 | 1132113323023201121 |
5 | 3130012234333423 |
6 | 114315104243545 |
7 | 10215062213660 |
oct | 1362773134131 |
9 | 320502126552 |
10 | 101333121113 |
11 | 39a7a9a5794 |
12 | 177803105b5 |
13 | 972ba731c3 |
14 | 4c94123dd7 |
15 | 29812bd728 |
hex | 1797ecb859 |
101333121113 has 8 divisors (see below), whose sum is σ = 116041368000. Its totient is φ = 86682895920.
The previous prime is 101333121107. The next prime is 101333121119. The reversal of 101333121113 is 311121333101.
It is an interprime number because it is at equal distance from previous prime (101333121107) and next prime (101333121119).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 101333121113 - 218 = 101332858969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101333121119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14501678 + ... + 14508663.
It is an arithmetic number, because the mean of its divisors is an integer number (14505171000).
Almost surely, 2101333121113 is an apocalyptic number.
It is an amenable number.
101333121113 is a deficient number, since it is larger than the sum of its proper divisors (14708246887).
101333121113 is an equidigital number, since it uses as much as digits as its factorization.
101333121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29010847.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 101333121113 its reverse (311121333101), we get a palindrome (412454454214).
The spelling of 101333121113 in words is "one hundred one billion, three hundred thirty-three million, one hundred twenty-one thousand, one hundred thirteen".
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