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101334113131 = 149680094719
BaseRepresentation
bin101111001011111111…
…0111101101101101011
3100200120011000022102011
41132113332331231223
53130013013110011
6114315141420351
710215103515106
oct1362776755553
9320504008364
10101334113131
1139a80513039
121778070a6b7
13972c02c8b4
144c9430173d
152981417621
hex1797fbdb6b

101334113131 has 4 divisors (see below), whose sum is σ = 102014208000. Its totient is φ = 100654018264.

The previous prime is 101334113039. The next prime is 101334113141. The reversal of 101334113131 is 131311433101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101334113131 - 225 = 101300558699 is a prime.

It is a super-2 number, since 2×1013341131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101334113141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340047211 + ... + 340047508.

It is an arithmetic number, because the mean of its divisors is an integer number (25503552000).

Almost surely, 2101334113131 is an apocalyptic number.

101334113131 is a deficient number, since it is larger than the sum of its proper divisors (680094869).

101334113131 is an equidigital number, since it uses as much as digits as its factorization.

101334113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 680094868.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 101334113131 its reverse (131311433101), we get a palindrome (232645546232).

The spelling of 101334113131 in words is "one hundred one billion, three hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 149 680094719 101334113131