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101340011433 = 340184239411
BaseRepresentation
bin101111001100001010…
…1011101101110101001
3100200120120002222100210
41132120111131232221
53130021020331213
6114315512051333
710215204612243
oct1363025355651
9320516088323
10101340011433
1139a83881571
1217782693b49
13973031650b
144c94dd9093
152981bd00c3
hex179855dba9

101340011433 has 8 divisors (see below), whose sum is σ = 135456974496. Its totient is φ = 67391528000.

The previous prime is 101340011413. The next prime is 101340011453. The reversal of 101340011433 is 334110043101.

It is an interprime number because it is at equal distance from previous prime (101340011413) and next prime (101340011453).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101340011433 - 26 = 101340011369 is a prime.

It is not an unprimeable number, because it can be changed into a prime (101340011413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42118503 + ... + 42120908.

It is an arithmetic number, because the mean of its divisors is an integer number (16932121812).

Almost surely, 2101340011433 is an apocalyptic number.

It is an amenable number.

101340011433 is a deficient number, since it is larger than the sum of its proper divisors (34116963063).

101340011433 is an equidigital number, since it uses as much as digits as its factorization.

101340011433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84239815.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 101340011433 its reverse (334110043101), we get a palindrome (435450054534).

The spelling of 101340011433 in words is "one hundred one billion, three hundred forty million, eleven thousand, four hundred thirty-three".

Divisors: 1 3 401 1203 84239411 252718233 33780003811 101340011433