Base | Representation |
---|---|
bin | 101111001100001010… |
… | …1011101101110101001 |
3 | 100200120120002222100210 |
4 | 1132120111131232221 |
5 | 3130021020331213 |
6 | 114315512051333 |
7 | 10215204612243 |
oct | 1363025355651 |
9 | 320516088323 |
10 | 101340011433 |
11 | 39a83881571 |
12 | 17782693b49 |
13 | 973031650b |
14 | 4c94dd9093 |
15 | 2981bd00c3 |
hex | 179855dba9 |
101340011433 has 8 divisors (see below), whose sum is σ = 135456974496. Its totient is φ = 67391528000.
The previous prime is 101340011413. The next prime is 101340011453. The reversal of 101340011433 is 334110043101.
It is an interprime number because it is at equal distance from previous prime (101340011413) and next prime (101340011453).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 101340011433 - 26 = 101340011369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (101340011413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42118503 + ... + 42120908.
It is an arithmetic number, because the mean of its divisors is an integer number (16932121812).
Almost surely, 2101340011433 is an apocalyptic number.
It is an amenable number.
101340011433 is a deficient number, since it is larger than the sum of its proper divisors (34116963063).
101340011433 is an equidigital number, since it uses as much as digits as its factorization.
101340011433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84239815.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 101340011433 its reverse (334110043101), we get a palindrome (435450054534).
The spelling of 101340011433 in words is "one hundred one billion, three hundred forty million, eleven thousand, four hundred thirty-three".
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