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101430312131 = 670315132077
BaseRepresentation
bin101111001110110110…
…1111011110011000011
3100200210212000201122002
41132131231323303003
53130212124442011
6114332455334215
710220352266501
oct1363555736303
9320725021562
10101430312131
113a01a848845
12177a898136b
139745c42295
144ca2dc3671
152989abac3b
hex179db7bcc3

101430312131 has 4 divisors (see below), whose sum is σ = 101445450912. Its totient is φ = 101415173352.

The previous prime is 101430312121. The next prime is 101430312149. The reversal of 101430312131 is 131213034101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101430312131 - 222 = 101426117827 is a prime.

It is a super-2 number, since 2×1014303121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101430312121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7559336 + ... + 7572741.

It is an arithmetic number, because the mean of its divisors is an integer number (25361362728).

Almost surely, 2101430312131 is an apocalyptic number.

101430312131 is a deficient number, since it is larger than the sum of its proper divisors (15138781).

101430312131 is an equidigital number, since it uses as much as digits as its factorization.

101430312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15138780.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 101430312131 its reverse (131213034101), we get a palindrome (232643346232).

The spelling of 101430312131 in words is "one hundred one billion, four hundred thirty million, three hundred twelve thousand, one hundred thirty-one".

Divisors: 1 6703 15132077 101430312131