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1014332341441 = 3156737576703
BaseRepresentation
bin11101100001010101110…
…10110011110011000001
310120222011120020210210211
432300222322303303001
5113104323034411231
62053551114154121
7133166046434026
oct16605272636301
93528146223724
101014332341441
113611a3188181
12144701a22941
13748606ba153
1437145b1154d
151b5b9b45eb1
hexec2aeb3cc1

1014332341441 has 8 divisors (see below), whose sum is σ = 1047073009664. Its totient is φ = 981592940160.

The previous prime is 1014332341411. The next prime is 1014332341447. The reversal of 1014332341441 is 1441432334101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1014332341441 - 25 = 1014332341409 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1014332341447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1470496 + ... + 2047198.

It is an arithmetic number, because the mean of its divisors is an integer number (130884126208).

Almost surely, 21014332341441 is an apocalyptic number.

It is an amenable number.

1014332341441 is a deficient number, since it is larger than the sum of its proper divisors (32740668223).

1014332341441 is an equidigital number, since it uses as much as digits as its factorization.

1014332341441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633471.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1014332341441 its reverse (1441432334101), we get a palindrome (2455764675542).

The spelling of 1014332341441 in words is "one trillion, fourteen billion, three hundred thirty-two million, three hundred forty-one thousand, four hundred forty-one".

Divisors: 1 31 56737 576703 1758847 17877793 32720398111 1014332341441